It is important to realize that not everyone thinks about or solves problems in the same way. Some people can read a problem and very quickly they have an idea or feeling about how they will reach their solution. Sometimes the most direct route to an answer is not so obvious and a little advanced planning makes things run more smoothly. In this example, we demonstrate the working of a problem via the two-column method, which is really just a way of organizing a plan of attack.
The problem is fairly complex and requires a number of logical and mathematical steps for its solution. We will walk you through the problem, along the way demonstrating how you might organize your approach using this two-column method. Of course, the first step is to read the problem, so here it is:
First it may be a good idea to make a list of the concepts dealt with in the problem. You could either do this in your head or on paper.
Start by listing the final desired quantity and how to get/why you want that quantity (in two separate columns). Then, in reverse order, list the steps you have to perform in order to get there. The last item in your list is your starting point. Essentially, we are making a reverse-outline of how we will solve the problem.
By balancing the second equation, it is determined that x = 4, y = 10:
P4O10 (s) + 6 H2O (l)
4 H3PO4 (aq). [Note that there is no change in the oxidation
state of phosphorus in this equation.]
With this information in hand, we can balance the first chemical equation and determine the number of moles of O2 consumed
per mole of P4 reacted. We can also determine the oxidation states of all the elements in the balanced reaction.
P4 (s) + 5 O2 (g)
P4O10 (s) + light + heat.
The oxidation numbers are P(0) in P4; O(0) in O2; P(+5),
O(-2) in P4O10. Using the oxidation numbers and the stoichiometry in
the balanced equation we know that there are 20 moles of electrons transferred to phosphorus atoms for
every 5 moles of O2 consumed. Now we have everything we need to execute the calculation and answer the question.